Wednesday, April 1, 2009
How and why the Mylow Motor works.
I think even the most devoted chanter of the TINSTAAFL mantra will admit that if one has a isolated North pole, lets it be attracted to a magnetic South pole and then waves a magic wand so that it instantly changed into a magnetic South pole, it will be free lunches all round.
Unfortunately I don't have a magic wand. What about an isolated pole? Well, I seem to remember from my sixth form physics class that we carried out an experimental determination of the force exerted on an isolated pole on the equator of a bar magnet. Of course the pole wasn't completely isolated but it was isolated enough for our purposes. It was a pole at the end of a barbell magnet (pictured below) which was much longer than the bar magnet we were investigating.
As you may remember the force law turns out to be an inverse cube law, the difference between the inverse square repulsion of one pole and the inverse square attraction of the other. Now if we take that barbell magnet and bend it, look what we get. A horseshoe magnet.
In line with the suggestions made in one of my Overunity.com posts we have cut out the interaction term physically represented by the metal in a bar magnet. The shortest distance between the two poles of the bent barbell horseshoe magnet is no longer metal but air. But the rotor magnets are also horseshoe magnets, albeit not very pronounced horseshoes.
So in the limit the Mylow Motor models relatively simple interactions between a lot of isolated poles (down Basil!). The interaction between a horseshoe stator magnet and a group of rotor magnets is illustrated diagrammatically here. The fact that the rotor poles are moving parallel to the stator poles indicates that the inverse third power law is involved. The inverse second power law is obviously involved in the approach and retreat of the rotor magnets to the clusters of magnets.
Thus we have within group interaction and between group interactions to play with. Now the essence of the Carnot power cycle is that it is made up of two power laws, an inverse fist power law (the isothermal legs) and an inverse 5/3 power law (the adiabatic legs). But we have two power laws here as well. In other words we have the necessary components for a BH magnetic power cycle analogous to the Carnot thermal cycle.
A Mylow cycle constructed from these components is illustrated here and below.
I have used the HB Cornell convention for plotting the cycle since it is in line with the stress-strain format that I'm familiar with, i.e. with the active action as ordinate and the passive as abscissa.
Since the Mylow Motor appears to be generating sufficient power to keep the rotor spinning against bearing resistance and windage the interactions between stator and rotor must somehow be cycling an area of the BH diagram. One thing's for sure. This analysis lends support to McCarthy's claim that getting power is just a matter of the way you move magnets around a three dimensional path. Let's just hope he's managed to exploit it as well as Mylow has.
As to the contentious question on where the power is coming from, it has always seemed clear to me that it's coming from the magnetic environment in exactly the same way power can be extracted from a positive and negative offset of the thermal environment or a positive and negative offset of the atmospheric environment. This implies that there must be some absolute zero magnetic potential (pressure) just as there is an absolute zero temperature and an absolute zero for atmospheric pressure.
Of course, such a radical change of viewpoint will create such a enormous amount of cognitive disturbance to the existing theoretical framework that it will only be adopted under the extreme duress of.......an explosion of magnetic motors, perhaps.